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翻訳と辞書　辞書検索 [ 開発暫定版 ] スポンサード リンク elongated triangular orthobicupola ： ウィキペディア英語版 elongated triangular orthobicupola In geometry, the elongated triangular orthobicupola is one of the Johnson solids (''J''35). As the name suggests, it can be constructed by elongating a triangular orthobicupola (''J''27) by inserting a hexagonal prism between its two halves. The resulting solid is superficially similar to the rhombicuboctahedron (one of the Archimedean solids), with the difference that it has threefold rotational symmetry about its axis instead of fourfold symmetry. == Volume == The volume of ''J''35 can be calculated as follows: ''J''35 consists of 2 cupolae and hexagonal prism. The two cupolae makes 1 cuboctahedron = 8 tetrahedra + 6 half-octahedra. 1 octahedron = 4 tetrahedra, so total we have 20 tetrahedra. What is the volume of a tetrahedron? Construct a tetrahedron having vertices in common with alternate vertices of a cube (of side $\backslash frac\; =\; \backslash frac\; V\_\; =\; \backslash frac\; \backslash frac^3\}\; =\; \backslash frac$ The hexagonal prism is more straightforward. The hexagon has area $6\; \backslash frac$, so $V\_\; =\; \backslash frac$ Finally $V\_\; +\; V\_\; =$ \frac + \frac numerical value: $V\_\{J\_\{35\}\}\; =\; 4.9550988153084743549606507192748$ 抄文引用元・出典: フリー百科事典『 ウィキペディア（Wikipedia）』 ■ウィキペディアで「elongated triangular orthobicupola」の詳細全文を読む スポンサード リンク 翻訳と辞書 : 翻訳のためのインターネットリソース Copyright(C) kotoba.ne.jp 1997-2016. All Rights Reserved.